Dear OF Team,
Is there a way to do the following test more nicely/shorter: tree[species=1 or species=8 or species=10 or species=11 or species=12 or species=16 or species=19 or species=22 or species=23]
What I'm looking for is something like this (e.g. in R): tree[species %in% c(1,8,10,11,12,16,19,22,23)]
Could this be implemented if doesn't exist yet?
Thanks! Andras
asked
Andras 184●8●38●55 accept rate: 0%
Accepted answer
Hi András,
In the latest version of Collect (3.22.x) there is a new function idm:array that you could use in combination with idm:contains function to simplify your expression, that will become:
idm:contains(idm:array(1,8,10,11,12,16,19,22,23), species)
Many thanks,
Open Foris Team
answered
Stefano (OF) ♦♦ 5.7k●1●1●9 accept rate: 19%
Hi,
It seems there is a problem with the expression above. If I try to use it to get a subset of a group of items, it doesn't work:
count(parent()/tree[idm:contains(idm:array(1,8,10,11,12,16,19,22,23),species)])
Am I doing something wrong?
The species code is an alphanumeric value, so it must be wrapped into single or double quotes. Try to use this expression instead: count(parent()/tree[idm:contains(idm:array('1','8','10','11','12','16','19','22','23'),species)])
However, I would split the expression into 2 separate calculated attributes, one attribute that says if a species in of a specific type and the other one that counts the trees of that species, and I would even move the count outside of the 'tree' entity, since it does not depend on the current tree item.
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